8x/4x^2+6=0

Solution for 8x/4x^2+6=0 equation:

8x/4x^2+6=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


8x+6*4x^2=0

Wy multiply elements

24x^2+8x=0

a = 24; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·24·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*24}=\frac{-16}{48}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*24}=\frac{0}{48}
=0
$